Question

For how time a force 10 N must have acted on a body of mass 25 kg to bring it to rest from a velocity of 2 ms​

Answer 1

ANSWER:

GIVEN:

force= 10N

mass= 25kg

u= 2m/s

v= 0m/s

FORMULA:

f= m(v-u/t)

10N = 25kg ( 0-2/t)

-10/25 = -2/t

( HERE MINUS SIGN WILL CUT)

10/25 ×2 =t

20/25 =t

4/5=t

THEREFORE,

TIME = 0.8 second (ANSWER)

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Answer 2

${{ \text{ \underline{{ \underline{Given \: data}}}}}:-}$

• A force 10 N must have acted on a body of mass 25 kg to bring it to rest from a velocity of 2 m/s.

${{ \text{ \underline{ { \underline{Solution}}}}}:-}$

Here,

• Force = F ( 10 N )
• Mass = m ( 25 kg )
• Acceleration = a
• Time = t
• Initial velocity = u ( 2 m/s² )
• Final velocity = v ( zero )

{Note: we need to bring body at rest hence, we take v = zero}

First we need to find acceleration of the body.

→ F = m × a

→ 10 = 25 × a

→ a = 10/25

→ a = 0.4 m/s²

Now, we use kinematical equation to find time, to bring it to rest.

→ v = u + at

→ 0 = 2 + (0.4)t

→ t = - 2/0.4

→ t = - 5 sec

Negative sign indicates force act's in opposite direction.

Hence, the body take rest after 5sec.