Question

for Li+2 ion r2:r5 wiil be

Answer 1

I hope it helps,......,...........

Answer 2

Answer:

The ratio of $r_2:r_n = 4:25$.

Explanation:

Formula used for the radius of the $n^{th}$ orbit will be,

$r_n=\frac{n^2\times 52.9}{Z}pm$   (in pm)

where,

$r_n$ = radius of $n^{th}$ orbit

n = number of orbit

Z = atomic number

Z for lithium ion is 3

$r_2=\frac{2^2\times 52.9}{3}pm$

$r_5=\frac{5^2\times 52.9}{3}pm$

$r_2:r_5$

$\frac{2^2\times 52.9}{3}pm:\frac{5^2\times 52.9}{3}pm$

$4:25$