Question

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can u solve question no. 24 ???​

Answer 1

Answer:

Lets see if it is;

f(0)=e

If x≠0

limx→0(1+x)1x

Now if 1x→0⇒x→∞

Therefore Limit can be modified as:

limx→∞(1+1x)x=e

(This limit is definition of ´e´)

Concluding:

limx→0f(x)=f(0)

Hence function is continuous on x=0 .

Step-by-step explanation:

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