Question

For motion of an object along the x - axis, the velocity v depends on the
displacement x as v = 3x2 - 2x, then what is the acceleration at x = 2m.
1) 48 ms 2
2) 80 ms 2
3) 18 ms 2
4) 10 ms 2​

Answer 1

SOLUTION

$= > \frac{</u><u>dV</u><u>}{dt} = \frac{(6x - 2)dx}{dt} = (6x - 2)v. \\ \\ = > so \: now \: a = (6x - 2)(3 {x}^{2} - 2x) \\ </u><u>I</u><u>n \: this \:question \: a \: is \: to \: be \: calculated \: for \: x = 2m \\ \\ = > (6 \times 2 - 2)(3 \times {2}^{2} - 2 \times 2) \\ = > (12 -2)(3 \times 4 - 4) \\ = > 10 \times 8 \\ = > 80m \: per \: sq.$

Option (2)✓

hope it helps ☺️

Answer 2

❤Hola dear ❤

dV= dt

(6x−2)dx =(6x−2)v.

=>so now,

a=(6x−2)(3x 2−2x)

In this question is to be calculated for x=2m=>(6×2−2)(3×2 2−2×2)

=>(12−2)(3×4−4)

=>10×8

=>80 m per sq.

.•♫•thanks •♫•.