Question

For one mole of a van der Waals gas when b = 0 and
T = 300 K, the PV vs, 1/V plot is shown below. The value of the
van der Waals constant a (atm. liter² mol⁻²) is :
(a) 1.0 (b) 4.5 (c) 1.5 (d) 3.0

Answer 1

answer : option (c) 1.5

for one mole of gas, Van Der Waals equation will be.... (P + a/V²)(V - b) = RT

given, b = 0

so, (P + a/V²) × V = RT

⇒PV + a/V = RT

⇒PV = (-a) 1/V + RT , here it is clear that if graph between PV and 1/V , -a is the slope and RT is the PV axis intercept.

now see graph,

slope of graph = (21.6 - 20.1)/(2.0 - 3.0) = -1.5

so, slope of graph = -a = -1.5

⇒a = 1.5

hence option (c) is correct choice.

also read similar questions : The compressibility factor for one mole of a van der waals gas at 0c and 100 atm pressure is found to be 0.5. Assuming t...

https://brainly.in/question/12529330

Write van der waals' equation for one mole of a real gas.

https://brainly.in/question/1238219