Chemistry, asked by Afjal8067, 11 months ago

The term that corrects for the attractive forces present in a
real gas in the van der Waals equation is
(a) nb (b) an²/V² (c) – an²/V² (d) – nb

Answers

Answered by Fatimakincsem
3

The term that corrects for the attractive forces present in a  real gas in the van der Waals equation is nb.

Option (A) is correct.

Explanation:

The Van der Waals equation can be given as:

(P + n^2  a  /  V^ 2 ) (V − nb)  = nRT

Where

  • P = pressure
  • V = volume
  • T = Absolute temperature
  • n = number of moles

The measure of force of attraction for n moles of real gas in the Van der Waals equation is given as:

(n^2a / V^2   ) and the correction for repulsive forces is nb.

Thus the term that corrects for the attractive forces present in a  real gas in the van der Waals equation is nb.

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Answered by rashich1219
2

The term that corrects for the attractive forces present in a  real gas in the van der Waals equation is\bold{\frac{an^{2}}{V^{2}}}

Step by step explanation:

Van der Waals equation of state for real gases.

The mathematical expression for this equation is as follows.

                         \bold{(P+\frac{an^{2}}{V^{2}})(V-nb)=nRT}

                         P = Pressure of the gas

                        V = Volume of the gas

                         n = Number of moles of the gas

                        R = Gas constant

                         T = Temperature of the gas

The force of attraction for "n' moles of real gas in the Van der Waals equation is given as follows.

                               \Rightarrow \bold{\frac{an^{2}}{V^{2}}}

The repulsive forces indicated by  - "nb"

Hence, correct option is "b".

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