Question

At constant volume and temperature conditions, the rate of
diffusion DA and DB of gases A and B having densities ⍴A
and ⍴B are related by the expression.
(a) DA = [DB ⍴A/⍴B]¹/²
(b) DA = [DB ⍴B/⍴A]¹/²
(c) DA = DB (⍴A/⍴B)¹/²
(d) DA = DB (⍴B/⍴A)¹/²

Answer 1

Answer:

At constant volume and temperature conditions, the rate of

diffusion DA and DB of gases A and B having densities ⍴A

and ⍴B are related by the expression is

(c) DA = DB (⍴A/⍴B)¹/² is your answer

Answer 2

The rate of  diffusion DA and DB of gases A and B having densities ⍴A

and ⍴B are related by the expression is $\bold{D_{A}=(D_{B}\frac{\rho _{B}}{\rho _{A}})^{1/2}}$.

Step by step explanation:

Graham's law of diffusion:

According to this law, the rate of diffusion of a gas is inversely proportional to the square root of its density.

The mathematical representation is as follows.

                                            $D\,\alpha \,\frac{1}{\sqrt{\rho }}$

For gas "A":

                                          $D_{A}\,\alpha \,\frac{1}{\sqrt{\rho_{A} }}$...........................(1)

For gas "B":

                                         $D_{B}\,\alpha \,\frac{1}{\sqrt{\rho_{B} }}$.........................(2)

divided equation (1) by (2).

                                       $\frac{D_{A}}{D_{B}}=\sqrt{\frac{\rho _{B}}{\rho _{A}}}$

                                     $\bold{D_{A}=(D_{B}\frac{\rho _{B}}{\rho _{A}})^{1/2}}$

Therefore, the expression is $\bold{D_{A}=(D_{B}\frac{\rho _{B}}{\rho _{A}})^{1/2}}$.

Hence, correct option is "d".

Read more or brainly.in-

https://brainly.in/question/3386934

https://brainly.in/question/6200495