Question

When r, P and M represent rate of diffusion, pressure and
molecular mass, respectively, then the ratio of the rates of
diffusion (rA / rB ) of two gases A and B, is given as :
(a) (PA / PB ) (MB /MA)¹/² (b) (PA / PB )¹/² (MB /MA )
(c) (PA / PB ) (MA /MB )¹/² (d) (PA / PB )¹/² (MA /MB )

Answer 1

Explanation:

When r, P and M represent rate of diffusion, pressure and

molecular mass, respectively, then the ratio of the rates of

diffusion (rA / rB ) of two gases A and B, is given as :

(a) (PA / PB ) (MB /MA)¹/²

(b) (PA / PB )¹/² (MB /MA )

(c) (PA / PB ) (MA /MB )¹/²

(d) (PA / PB )¹/² (MA /MB )

Answer 2

The diffusion rate of two gases "A" and "B" is $\bold{\frac{\rho _{A}}{\rho _{B}}(\frac{M_{B}}{M_{A}})^{1/2}}$.

Step by step explanation:

Diffusion:

It is defined as the random movement of particles, in a solution or gas ,form a region of higher concentration to a region of lower concentration.

Rate of diffusion $r\,\alpha\, p$

                            $r=\frac{1}{\sqrt{M}}$                     ($\therefore r\,\alpha \,\frac{P}{\sqrt{M}}$)

For gas  "A":

                           $r_{A}\,\alpha \,\frac{\rho _{A}}{\sqrt{M_{A}}}$....................................(1)

For gas "B":

                         $r_{B}\,\alpha \,\frac{\rho _{B}}{\sqrt{M_{B}}}$......................................(2)

Divided by equation (1) by equation (2)

                    $\frac{r_{A}}{r_{B}}=\frac{\rho _{A}}{\rho _{B}}.\sqrt{\frac{M_{B}}{M_{A}}}$

                            or

                       $\Rightarrow \frac{\rho _{A}}{\rho _{B}}(\frac{M_{B}}{M_{A}})^{1/2}$

Therefore, The diffusion rate of two gases "A" and "B" is $\bold{\frac{\rho _{A}}{\rho _{B}}(\frac{M_{B}}{M_{A}})^{1/2}}$.

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