for positive real numbers x,y,z show that x²/yx + y²/xz+z²/xy>=3
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Answer:
Three positive real numbers x,y,z satisfy the equations x
2
+
3
xy+y
2
=25,y
2
+z
2
=9 and x
2
+xz+z
2
=16. Then the value of xy+2yz+
3
xz is
Step-by-step explanation:
Answer 30
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