Question

For preparing 300 ml 1 Molar h2SO4 soln, how much volume of water and sulphuric acid do we need

Answer 1

Answer:

$M = \frac{N_{H_{2}SO_{4}} }{V (L)} \\1 = \frac{N}{0.3}$

No. of moles of H2SO4 = 0.3

Volume of H2SO4 = 22.4 x 0.3 = 6.72 mL

Volume of Water = 300 - 6.72 = 293.28 mL