Question

For reaction 6 moles of H2 is taken with excess of N2 gas mass of ammonia gas produced is

Answer 1

Answer is 68 grams

3H2 +N2---------2NH3
IT means 3 moles of h2
produces 2 moles of nh3

so it means 1 mole of h2 makes 2/3 moles of nh3
so 6 moles of h2 makes 2÷3×6=4 moles of nh3

moles =given mass÷molar mass
4×17 (molar mass of nh3)=given mass

it means ans=68g

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Answer 2

heya..

✔here is ua answer:

✔In this reaction 2 moles of Nitrogen and 3 moles of hydrogen gives 2 moles of ammonia.

✔It is given that 6 moles of hydrogen is taken and excess of nitrogen is taken. So hydrogen will act as a limiting reagent.{Keep in mind that the amount of product formed will be dependent on the amount of limiting reagent taken}( Here it is hydrogen.)

✔Now, from here its simple stoichiometry and unitary method.

» 3 moles of hydrogen give 2 moles of NH3

»Then 1 mole of H2 will give 2/3 mole of NH3

» So 6 moles of H2 will give 2/3×6 moles of NH3

That is 4 moles of NH3 will be formed.

1 mole of NH3 weighs 17g so 4 moles will weigh 68g.

✔So option 4 is correct.

hope it helps..!!❤