For reaction a+b=products it is found that the order of a is 1 and order of b is half when the conc. Of both
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What, for the reaction A+B =product is found that the order of A is 2 and the order of B is 3 in the rate law expression when the concentration of both doubles and the rate will increase by the factor?
The expression for rate law for the above reaction is given by:
r=k[A]2[B]3
where k denotes the rate constant.
Now when the concentration of both species are doubled, the new rate of the reaction is given by:
r′=k[2A]2[2B]3=32k[A][B]
Diving the new rate by the original rate of the reaction, we get:
r′r=32
thus rate increases by a factor of 32.
This might help you mate
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