For reaction aA = lL + mM. In condition of suddenly volume increase, degree of dissociation is decrease it represent that. (1) a < (l + m) (2) a = (l+For reaction aA = lL + mM. In condition of suddenly volume increase, degree of dissociation is decrease it represent that. (1) a < (l + m) (2) a = (l+ m) (3) a = (l m) (4) a > (l + m) m) (3) a = (l m) (4) a > (l + m)
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Answered by
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It represents a > (l + m).
Explanation:
Given,
aA = lL + mM
As we know,
y ∝ decreases which mean r * n goes reverse,
∵ a > (l + m)
because when volume increases immediately, r * n moves towards the place where the mole is increasing.
Thus, option 4 is the correct answer.
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Answer: a > (l + m)
Explanation:Given,
aA = lL + mM
As we know,
y ∝ decreases which mean r * n goes reverse,
∵ a > (l + m)
because when volume increases immediately, r * n moves towards the place where the mole is increasing.
Thus, option 4 is the correct answer.
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