the identity for for) (x+b) is x²+(a+b)x+ab
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Answer:
it is (x+b)(x+a)=
x²+(a+b)x ab
eg- (100+2)(100+1)
100² +(1+2)100 +1×2
10000+300+2
10300+2=
10302
hope it helps you,friend
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