Question

for real no a and b≠0, if the point of intersection of the straight lines x-a/1 = y-1/2 = z-1/3 and x-4/b = y-6/3 = z-7/3, lies on the plane x+2y-z=8, then find a-b.​

Answer 1

Step-by-step explanation:

Answer

Correct option is

B

(10,10,−3)

We have line,

3

x−1

=

4

y+2

=

−2

z−3