For Root2x^ -5x +Root2 =0 find the value of the discriminant
Answers
Answered by
45
Answer:
Discreminant = 17
Explanation:
Compare √2x² -5x +√2 =0
with ax²+bx+c = 0 , we get
a=√2 , b = -5 , c = √2
Discreminant (D) = b²-4ac
= (-5)²-4×√2×√2
= 25 - 4×2
= 25 - 8
= 17
Therefore,
Discreminant = 17
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anshuyadav92:
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Which of the following equation is quadratic x^square -2x +5 = x^square
Find this qustion
ir is not a quadratic equation. it is a linear equation in one variable x
post it in braiy
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But it is not a quadratic equation naa
Answered by
10
Answer:
Discriminant = 17
Step-by-step explanation:
By Comparing √2x² -5x +√2 =0 with standard form of quadratic equation ax²+bx+c = 0 , we get
a=√2
b = -5
c = √2
Discriminant (Δ) = b²-4ac
= (-5)²-4×√2×√2
= 25 - 4×2
= 25 - 8
= 17
Therefore,
Discriminant = 17
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