Math, asked by anshuyadav92, 1 year ago

For Root2x^ -5x +Root2 =0 find the value of the discriminant​

Answers

Answered by mysticd
45

Answer:

Discreminant = 17

Explanation:

Compare √2x² -5x +√2 =0

with ax²+bx+c = 0 , we get

a=√2 , b = -5 , c = √2

Discreminant (D) = b²-4ac

= (-5)²-4×√2×√2

= 25 - 4×2

= 25 - 8

= 17

Therefore,

Discreminant = 17

••••

anshuyadav92: Thank u
mysticd: press red heart
anshuyadav92: Which of the following equation is quadratic x^square -2x +5 = x^square
anshuyadav92: Find this qustion
mysticd: ir is not a quadratic equation. it is a linear equation in one variable x
mysticd: post it in braiy
mysticd: brainly
anshuyadav92: But it is not a quadratic equation naa
Answered by toptengalaxyj2
10

Answer:

Discriminant = 17

Step-by-step explanation:

By Comparing √2x² -5x +√2 =0  with standard form of quadratic equation ax²+bx+c = 0 , we get

a=√2

b = -5

c = √2

Discriminant (Δ) = b²-4ac

= (-5)²-4×√2×√2

= 25 - 4×2

= 25 - 8

= 17

Therefore,

Discriminant = 17

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