Question

for sinusoidal signal x[n]=5sin[6πn /35] solve it fast​

Answer 1

Answer:

2π.m

Ω

Here, Ω = 2

So, N =

2π

·m = π

2

which is non-periodic.

(B) x[n] = 4 sin [0·2πn]

Ω = 0·2π

N =

2π

· m =

2

· m = 10 × 1 = 10

Ω 0·2π

i.e., periodic with period = 10.

(C) x[n] = 4 cos [6πn]

Ω = 6

N =

2π

· m =

2π

· m = 2 × 3 6 = 1

Ω 6π

i.e., periodic with period = 1

(D)

x[n] = 4 cos

6πn

35

Ω =

6π

35

N =

2π

· m =

2π

· m =

2 × 35

· m

Ω 6π/35 6

= 35 with m = 3