Question

for Solving the equation 3x-2y = 6 s 2x +y=11 by chamer's rule find the value of D​

Answer 1

Answer:

3x-2y = 6

2x+y = 11

for solving these eq6 by cramers rule determinant of matrix forces by coeff of x and y is not zero.

now determinant = >

for equation of type

a1x+b1y+c1 = 0 and a2x+b2y+c2 = 0

\begin{gathered} \binom{c1 \: \: \: a1}{c2 \: \: a2} \\ = c1a2 - c2a1\end{gathered}

(

c2a2

c1a1

)

=c1a2−c2a1

on putting values

[(-6) ×2] - [(-11) ×3]

=>21

Answer 2

$\large\bf\underline\red{Answer \: :-}$

Given equation :

3x-2y = 6

2x +y=11

By Cramer's Rule

Finding D

$\small\sf\longrightarrow{D = \begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\left|\begin{array}{cc} \sf 3 & \sf - 2 \\ \sf2 & \sf1 \end{array}\right| </p><p> \end{gathered} \end{gathered} \end{gathered}\end{gathered} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \small \sf \longrightarrow{D = ( 3 \times 1) - (2 \times - 2)} \\ \\ \small \sf \longrightarrow{D = 3 - ( - 4) = 3 + 4} \: \\ \\ \small \bf \longrightarrow \red{D = 7} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

D = 7

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