for some integer a every even integer 15 of the form
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Step-by-step explanation:
m
m+1
2m
2m+1
Answer :
C
Solution :
We know that, even integers are 2,4,6… <br> So, it can be written in the form of 2m. <br> Where m=integer=Z [since, integer is represented by Z] <br> or m=…,1,0,1,2,3… <br>
2m=…,2,0,2,4,6 <br> Altenated Method <br> Let 'a' be a positive integer. On dividing 'a' by 2, let m be the quotient and r be the remaintder. Then, by Euclid's division algorithm, we have <br> a=2m+r, where
i.e. r=0 and r=1 <br>
a=2m or a=2m+1 <br> When, a=2m for some integer m, then clearly a is given
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