for some integer m,every even integer is of the form
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Answer:
m
m+1
2m
2m+1
Step-by-step explanation:
We know that, even integers are 2,4,6… <br> So, it can be written in the form of 2m. Where m=integer=Z [since, integer is represented by Z] or m=…,1,0,1,2,3…
2m=…,2,0,2,4,6 Altenated Method Let 'a' be a positive integer. On dividing 'a' by 2, let m be the quotient and r be the remaintder. Then, by Euclid's division algorithm, we have a=2m+r, where
i.e. r=0 and r=1
a=2m or a=2m+1 . When, a=2m for some integer m, then clearly a is given
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