For some integer m, every even integer is of the form
(A) m (B) m + 1 (C) 2m (D) 2m + 1
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113
For some integer m, ever even integer is of the form
(C) 2m.
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(C) 2m.
Hope it helps.
Please mark my answer as brainliest.
Thank You.
Answered by
62
Answer: The answer is (C) 2m.
Step-by-step explanation: We are to find the correct form of every even integer for some integer 'm'.
We know that an even integer is one which is divisible by 2, so every integer which is a multiple of 2 must be an even integer.
Therefore, for an integer 'm', every even integer must be of the form
2 × m = 2m.
Thus, (C) is the correct option.
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