Question

For some integer m, show that every even integer is of the form 2m

Answer 1

let a be any +ve integer and b=2
by euclid division algorithm ,a=bq+r  0<_r<b
a=2q+r  0<_r <2
i.e r =0,1
so r=0,a=2q+0 = a=2q i.e in d form a=2m
& if u want to proof dt every +ve odd integer is of form 2m+1, we will put ,r=1,a=2q+1 
hope u will like my efforts 

Answer 2

Yes. all even positive integers are of the form  2m.    where m = integer.

all odd integers are of the form   2m+1