For some integer 'x. every odd integer is of the form
(a)"2x
(b)x+1
(c) x-1
(d) 2x+1
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Answer:
(D)
Step-by-step explanation:
In order to solve this, let's take a random value of x and proceed further.
Let's take x as 3 and 2
2(3) = 6 , 2(2) = 4. Both 6 and 4 are even
3 + 1 = 4 , 2 + 1 = 3. One of them is odd, but we need all the numbers as odd
3 - 1 = 2 , 2 - 1 = 1, Again, we need all the numbers as odd.
2(3) + 1 = 7, 2(2) + 1 = 5. Yes, we both odd, so this is the answer.
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