for strong acid base neutralisation energy for 1 mole H2O formation is -57.1KJ. If 0.25 mole of strong monoprotic acid is reacted with 0.5 mole of strong base then enthalpy of neutralisation is
Answers
Answered by
23
Here the concept that applies is that of Limiting Reactant.
1H+ +1OH- >1H2O and the heat change is -57kJ
if we have 0.25 mole H+ then it will react with 0.25 OH- to produce 0.25mol water.
As the amount of water produced is 1/4 times of 1mole so the heat produced will also be -57.1/4=14.26kJ
Answered by
5
Enthalpy of neutralisation-0.25× 57.1 kJ
Similar questions