Question

For the circuit as shown in the figure, the net charge on upper plate will be (Area of each plate is A and separation between two consecutive plates is d)​

Answer 1

Given:

Circuit has been provided.

To find:

Net charge on upper plate?

Calculation:

Now, first of all, we will simplify the circuit by assigning potential drops to the plates. We can see that the capacitors are in parallel combination.

So, net capacitance :

$C_{net} = C + C$

$\implies C_{net} = 2C$

$\implies C_{net} = \dfrac{2A \epsilon_{0}}{d}$

Now,

Charge held by the upper capacitor will be :

$q = CV$

$\implies q = \dfrac{A \epsilon_{0} }{d} V$

So , final answer is:

$\boxed{ \bf q = \dfrac{A \epsilon_{0} }{d} V}$