Question

For the coagulation of 20 ml of gold sol, 20 mL of M/20 NaCl is required. The flocculation value of NaCl is

Answer 1

Answer:

Explanation:

Answer:

50

Explanation:

first calulate the milimolesof NaCl = 1/20 × 20 = 1 milimole

now 1 milimoles is required for cougualtion of 20 ml therfore for one litter 50 milimoles are required.

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Answer 2

The flocculation value of NaCl is 50.

Explanation:

The minimum concentration of an electrolyte required to cause flocculation or coagulation of a solution is known as flocculation value. Flocculation value is expressed in terms of millimoles per litre.

Therefore,

• 20 mL of $\frac{M}{20}$ NaCl contains = $20\times\frac{1}{20}$
• 20 mL of $\frac{M}{20}$ NaCl contains = 1 millimole
• 20 mL of Gold requires 1 millimole of NaCl for coagulation.

Thus,

• 1000 mL of Gold requires = $1\times\frac{1000}{20}$
• 1000 mL of Gold requires = 50 millimoles

1000 mL of Gold requires 50 millimoles of  $\frac{M}{20}$ NaCl for coagulation.