Question

The equations of motion of a projectile thrown in x-y plane from origin are x = 8t, y = 6t - 10t2

then the

angle of projectile is​

Answer 1

answer:

53°

Explanation:

x=8t,y=6t-10t^2

this is of form ,x=at,y=bt-ct^2

therefore tan x=b/a

= 6/8

x=tan^-1(6/8)

=tan^-1(3/4)

=53°