Question

for the equation 7x-3y=15.,expressx in terms of y and check if the line represrented by the given equation intersect y axis at y=-5.

Answer 1

Given equation is 
7x - 3y = 15
7x = 3y + 15
$x = \frac{3y}{7} + \frac{15}{7}$

when y = -5

$x = \frac{3(-5)}{7} + \frac{15}{7}$

$x = \frac{-15}{7} + \frac{15}{7}$

x = 0

Therefore, we can say that, the line intersects the y axis at y = -5. At the point (0, -5)

Answer 2

so given 

7x - 3y = 15

⇒ x = $\frac{15+3y}{7}$

so putting y = -5 we get 

x = $\frac{15+3(-5)}{7}$

⇒ x = 0

hence it does intersect y axis at y = -5