Question

For the equations given below, tell the nature of graphs. (a) y =2x^(2) (b) y =-4x^(2) +6 (c) y = 6 ^(-4x) (d) y = 4(1 -e^(-2x)) (e) y =(4)/(x) (f) y =-(2)/(x)

Answer 1

Answer:

1) for the equation y=2x^2

the graph gonna be a parabola with vertex at (0,0)

2)  for y=4x^2+6

   it is also a parabola with veertex at (0,6)

3) for y =6^( -4x)

     at x =0 ;y= 1

         x=1 ; y=6^-4

4) for y= 4(1-e^-2x)

       at x=0 ; y=0

       for all x≤0 the graph gonna be a straight line close to infinity

5) for y= 4/x

     at x=0; y=∞

          at y=0;x=∞

             at x=4 ; y=1

              at y=4 ; x=1