For the following airthmatic progression 122, 116, 110,... find the first 'n' for which Tn is negative.
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tn=a+(n-1)d
here
a=122
d=-6
tn=122+(n-1)-6
=122-(n-1)6
so here the value of tn will be negative when the value of n is
should be greater than or equal to 22
here
a=122
d=-6
tn=122+(n-1)-6
=122-(n-1)6
so here the value of tn will be negative when the value of n is
should be greater than or equal to 22
Anonymous:
how?
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