Chemistry, asked by piyushloonker13, 11 months ago

For the following equilibrium Kp = 6.3 x 1024 at 1000k
NO(g) + O2(g) N O2(g) + O2(g)
What is Kp for the reverse reaction?​

Answers

Answered by vivekanandamsc19
1

Answer:

generally Kp for forward reaction = 1/ Kp for backward reaction .so that.

kp for reverse reaction = 1/6.3×10(24)

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