Chemistry, asked by tarkeshwarrai7367, 11 months ago

for the following equilibrium n2o4(g)⇌2no2(g) in gaseous phase, no2 is 50% of the total volume when equilibrium is set up. hence, percent of dissociation of n2o4 isA. 50% B. 25% C.66.66% D.33.33%

Answers

Answered by edwin555
18

Look at the question very closely;

We have been given that the equilibrium of dinitrogentetraoxide and nitrogen (IV) Oxide is N2O4(g)⇌2NO2(g) in gaseous phase, and NO2 is 50% of the total volume when equilibrium is set up.

Hence, percent of dissociation of N2O4 will be 25%.

the mole fraction of N2O4 is 1/3 and that one of NO2 is 2/3

Then this implies that 2/3 gives 50%

Therefor 1/3 would give what percentage?

1/3 x 50 x 3/2 = 25%

Answered by shilpikumari60
11

Answer:

2/3 is right answer

Explanation:

hope this answer will help you a lot

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