Question

For the following reaction,

H 2(g)+ I2(g)~ 2HI(g),

If initially 25 mL of H 2 and 20 mL of I 2 are present in a container

and at equilibrium 30 mL of HI is formed then calculate

equilibrium constant.

Answer 1

K= (HI)^2 ÷(I2) × (H2)
= (30)^2 ÷ 10×15
= 6

( x l2 + x H2 =2x HI
30 HI = 2×15 = 15 l2 + 15 H2