Question

for the given equation, x=?
TX
=
S
1
2s 3(s? +1) 6(s? +4)
Answer
1 1
-
cos
A.
B.
cos--cos 27
sin 27
C.
D. None of these
​

Answer 1

Answer:

and with F(t) = t2, using part (b) of the last question gives the answer. 2 ... and this integral is evaluated by integrating by parts twice using the following ... 4. Using Theorem 2.3 we get. L. {∫ t. 0 cos(au) − cos(bu) u du. } = 1 s. ∫ ∞ s u ... and using the standard form (Appendix B):. L{tx−1} = {x} sx with x = 3/2 gives. L{sin(. √.