Question

for the given network reading of ammeter is​

Answer 1

See first of all its a Wheatstone problem.So forget the 5ohm

Now after calculating u will get equivalent resistance as 36/7 ohm((3+6)||(8+4)).

So now calculate the current.

I=V/r

i.e

I=£/36/7

i.e

I=7£/36

Therefore reading is 7£/36...

Answer 2

Answer:

See first of all its a Wheatstone problem.So forget

the 5ohm

Now after calculating u will get equivalent

resistance as 36/7 ohm((3+6)||(8+4)).

So now calculate the current.

EV/r

i.e

-£/36/7

i.e

1=7£/36

Therefore reading is 7£/36...

Explanation: