Question

For the given reaction at equilibrium :
AgNO3(s) = Ag(s) + NO2(g) + O2(9)
If total pressure at equilibrium is P. then calculate Kp for the given reaction.​

Answer 1

Answer: The expression of $K_p$ for the equation is written below.

Explanation:

We are given:

The partial pressure of a gas is given by Raoult's law, which is:

$p_A=p_T\times \chi_A$

We are given:

Total pressure = P

$p_{NO_2}=P\times \chi_{NO_2}\\\\p_{O_2}=P\times \chi_{O_2}$

For the given chemical equation:

$2AgNO_3(s)\rightleftharpoons 2Ag(s)+2NO_2(g)+O_2(g)$

In the expression of $K_p$, no solid or liquid chemical species appear.

The expression of $K_p$ for above equation follows:

$K_p=p_{NO_2}^2\times p_{O_2}$

Putting values in above equation follows:

$K_p=(P\times \chi_{NO_2})^2\times (P\times \chi_{O_2})\\\\K_p=P^3(\chi_{NO_2}\times \chi_{O_2})$

Hence, the expression of $K_p$ for the equation is written above.