Question

for the given reaction PCL5 is break down into pcl3 + cl2 if 1 Mol of PCL5 is introduced into the vessel at equilibrium if it gives 50% product find KC for the reaction.?​

Answer 1

Explanation:

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Answer 2

Given reaction is

$PCl_{5}\binom{\rightarrow}{\leftarrow} PCl_{3}+PCl_{2}$

Also the degree of dissociation is 50%

$\alpha = 0.5$

Refer the attachment for further details and dereivation

As it is becoming Harder for me to continue further with keyboard

We know that The formation of prodyct is given by

$product = c \alpha$

$where \: c \: is \: initial \: concentration \: of \: pcl5$

$\alpha \: is \: degree \: of \: dissociation$

Further solving is done in Attachment

$\huge{\green{K_{c}=0.5}}$