For the home in the previous question, what size array (in kW to the nearest tenth 0.1) would be needed to meet their target of 60% of their annual energy if their home receives 2008 full sun hours annually you assume an 85% system efficiency.
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11
Answer:
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Explanation:
Answered by
0
Answer:
4.7
Explanation:
The previous requirement was 7980 kW.
Efficiency - 0.85
Full sun hours - 2008
System size - 7980/2008/0.85 = approx. 4.7
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