Physics, asked by arishk85, 6 months ago

For the magnetic circuit shown in figure 21.19 the reluctance of the central limb (PS) is 10 × 105 AT/Wb and the reluctance of the outer limbs (PTS and PQS) are same and equal to 15 × 105 AT/Wb. To produce 0.5 mWb in PQS, the mmf to be produced by the coil is: (A) 750 AT (B) 1750 AT (C) 250 AT (D) 1500 AT.

Answers

Answered by siriiiiii
9

Explanation:

For the magnetic circuit shown in figure below the reluctance of the central limb be is 10 x 105 AT/Wb and the reluctance of the outer limbs (bafe and bcde) are same and equal to 15 x 105 AT/ Wb. What is the mmf to be provided by the coil to produce 0.5 mWb in bcde? .

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