Question

For the $\mathrm{H}_2$ molecule which spin states correspond to bonding? and which spin states correspond to anti-bonding?

Answer 1

Correct conclusion but incorrect argument. The full wave function - not only its spatial part - must be antisymmetric. The spatial part can be symmetric if the spin part is antisymmetric.

In fact in the case of H2H2 the bonding is for a symmetric spatial wavefunction . Indeed “singlet” usually refers to spin-singlet, which is S=0S=0 and antisymmetric, thus forcing the spatial part to be symmetric under permutation.

Answer 2

Hey mate ^_^

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Answer:
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In the case of H2 the bonding is for a symmetric spatial wave-function. Indeed “singlet” usually refers to spin-singlet, which is S=0 and antisymmetric, thus forcing the spatial part to be symmetric under permutation.

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