For the polynomial 3x^2-4x-4,find sum of the squares of the zeros
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Answered by
2
Answer:
3x^2-4x-4
=3x^2-6x+2x-4
=3x(x-2)-2(x-2)
3x-2=0. x-2=0
x=2\3. x= 2
As x cannot be negative so x=2
Answered by
2
Answer:
3x^2-4x-4
by splitting the middle term
3x^2-6x+2x-4=0
3x(x-2)+2(x-2)=0
(3x+2)(x-2)=0
(3x-2)=0
3x=2
x=2/3--(1)
(x-2)=0
x=2--(2)
(1) & (2) are two zeroes
a^2+b^2=
2^2/3^2+ 2^2
4/9+4=
4/9+36/9=
40/9
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