For the polynomial f(x) = x3 + ax2 + bx + C, the
sum of two zeroes is 0, then find the relation
between a, b and c.
Answers
Answered by
15
Answer:
Step-by-step explanation:
sum of two roots is zero
sum of roots is-b/a for ax3 + bx2 + cx + d
here sum is -a
so third root is -a
so f(-a)=0
-a^3+a^3-ab+c=0
-ab+c=0
c=ab
that's the relation
Answered by
7
ab = c is the relation between a, b and c if for polynomial f(x) = x³ + ax² + bx + c , sum of two zeroes is 0
Given :
- Polynomial function
- f(x) = x³ + ax² + bx + c
- sum of two zeroes is 0
To Find:
- The relation between a, b and c
Solution:
Step 1:
Assume that roots of f(x) = x³ + ax² + bx + c are
m , - m and n
As sum of m and - m = 0
Step 2:
Sum of roots = - a
m + (-m) + n = - a
=> n = - a
Hence one of the root is - a
Step 3:
As -a is one of the root hence f(-a) = 0
(-a)³ + a(-a)² + b(-a) + c = 0
=> -a³ + a³ -ab + c = 0
=> -ab + c = 0
=> ab = c
ab = c is the relation between a, b and c if for polynomial f(x) = x³ + ax² + bx + c , sum of two zeroes is 0
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