Question

solve the following qudratic equation
1) 5m2 + 2m +1=0
solution:
$5 {m} {}^{2} + 2m + 1 = 0$
comparing it with the standard form
$a {x}^{2} + bx + c = 0$
a=5,b=2,c=0

${b} {}^{2} - 4ac = {2}^{2} - 4 \times 5 \times 1 \\ = 4 - 20 = - 16 \\ {b }^{2} - 4ac < 0$
the root of quadratic equation are not real
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Answer 1

Answer :

m=1. or -2/5

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