Question

For the polynomial p(x)=x^(5)+4x^(3)-5x^(2)+x-1 one of the factors is
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Answer 1

$\fbox\blue {A} \fbox\pink{n} \fbox\orange{s} \fbox\purple{w} \fbox\green{e} \fbox\red{r}$

x-1 is a factor of the given polynomial

Step-by-step explanation:

x-1 = 0

=> x = 1

Substitute x in the given polynomial ..

$x^5+4x^3-5x^2+x-1$

${\implies{1^5+4(1)^3-5(1)^2+1-1}}$

${\implies{1+4-5+1-1}}$

${\implies{0}}$

${\therefore {x-1=0\ is\ a\ factor\ of\ the\ given\ polynomial }}$