Question

for the quadratic equation x²+2x-15=0, determine which of the following are solution (s) : (a) X=-5(b)X=-3(c) X=3​

Answer 1

Answer:

3,-5

Step-by-step explanation:

x^2+5x-3x-15

X(X+5)-3(X+5)=0

(x-3) (X+5)=0

X belongs to 3,-5

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Answer 2

Step-by-step explanation:

If we substitute x= -5 ,

25-10-15=0

If we substitute x= -3 ,

9-6-15 is not equal to 0

If we substitute x= 3 ,

9+6-15=0

So for this quadratic equation (a) and (c) are solutions.

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