Chemistry, asked by abdullahdelhi1234, 10 months ago

For the reaction 2 N2 H4 (l) + N2 O4 (l) -------> 3 N2 (g) + 4H2 O(l) , if 160 g of N2 H4 is mixed with 160 g N2O4, the yield of H2O is

Answers

Answered by ranasalman70510
0

Answer:

is not right answer

Explanation:

Answered by jatinraghav123
0

Consider the reaction between

N

2

H

4

N2H4 and

N

2

O

4

N2O4:

2

N

2

H

4

(

g

)

+

N

2

O

4

(

g

)

3

N

2

(

g

)

+

4

H

2

O

(

g

)

2N2H4(g) + N2O4(g) ⟶ 3N2(g) + 4H2O(g). A reaction vessel initially contains

24.5

g

N

2

H

4

24.5g N2H4 and

74.9

g

o

f

N

2

O

4

74.9g ofN2O4.

a) Calculate the mass of

N

2

O

4

N2O4 that will be in the reaction vessel once the reactants have reacted as much as possible (Assume 100% yield)

b) Calculate the mass of

N

2

N2 that will be in the reaction vessel once the reactants have reacted as much as possible (Assume 100% yield)

c) Calculate the mass of

H

2

O

H2O that will be in the reaction vessel once the reactants have reacted as much as possible. (Assume 100% yield)

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