Question

For the reaction:
2MnO2 + 4KOH + O2 + Cl2 → 2KMnO4 + 2KCl + 2H2O
There is 100 g of each reactant available. Which reagent is the limiting
reagent?
[Molar Masses: MnO2 = 86.9; KOH=56.1; O2 =32.0; Cl2 =70.9]
(A) MnO2
(B) O2
(C) KOH
(D) Cl2
plzz answer step by step​

Answer 1

Explanation:

Referring directly to your balanced chemical equation, there are

100.0

⋅

g

86.94

⋅

g

⋅

m

o

l

−

1

M

n

O

2

=

1.15

⋅

m

o

l

100.0

⋅

g

56.11

⋅

g

⋅

m

o

l

−

1

K

O

H

=

1.78

⋅

m

o

l

100.0

⋅

g

32.00

⋅

g

⋅

m

o

l

−

1

O

2

=

3.13

⋅

m

o

l

And,

100.0

⋅

g

70.9

⋅

g

⋅

m

o

l

−

1

C

l

2

=

1.41

⋅

m

o

l