Question

For the reaction at 298 K, 1/2 N2 (g) + 3/2 H2 (g) → NH3 (g) ; Δ H = - 46 kJ(a) What is the value of Δng?
(b) Calculate the value of Δ U at 298 K?​

Answer 1

Answer:

When a chemical reaction occurs, there is a characteristic change in enthalpy. The enthalpy change for a reaction is typically written after a balanced chemical equation and on the same line. For example, when two moles of hydrogen react with one mole of oxygen to make two moles of water, the characteristic enthalpy change is 570 kJ. We write the equation as

2 H2(g) + O2(g) → 2 H2O(ℓ) ΔH = −570 kJ