Question

For the reaction at 298 K 2 A+ B<===> C, ◇H=400 kJ mol and ◇S=0.25 kJ K-1 mol-1
At what temperature will the reaction become spontaneous considering ◇H and ◇S to be constant over the temperature range
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Answer 1

Answer:

S=H/T

Explanation:

T=H/S=400/0.25=40000/25=1600K

Answer 2

Answer:

2000 K

Explanation:

Given reaction as :

2 A + B ⇒  C

= > Δ H = 400 kJ mol⁻¹ and Δ S = 0.2 kJ K⁻¹ mol⁻¹

Let is first calculate temperature at which the reaction will be in equilibrium.

i.e. Δ G = 0

We know :

Δ G = Δ H - T Δ S

= > Δ H - T Δ S = 0

= > T = Δ H / Δ S

Putting given values here we get :

= > T = 400 / 0.2 K

= > T = 2000 K

Therefore , the required temperature is 2000 K .