Question

For the reaction CO(g) + 2H2 (g) gives CH3OH (g) if active mass of CO is kept constant and active mass of H2 is tripled then the rate of forward reaction will become

Answer 1

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Answer 2

Answer: The rate of forward reaction will become 9 times.

Explanation: Rate law says that rate of a reaction is directly proportional to the active mass of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$CO(g)+2H_2\rightarrow CH_3OH$

$Rate=r=k[CO]^1[H_2]^2$

k= rate constant

Given: Active mass of $CO$ is kept constant and active mass of $H_2$ is tripled

${\text {new rate}}=r'=k[CO]^1[3\times H_2]^2$

$r'=k[CO]^1[3]^2\times [H_2]^2$

$r'=k[CO]^19\times [H_2]^2$

$r'=9\times r$

Thus new rate will become 9 times the original rate.